Calculate the standard enthalpy change ( in kJ mol^(-1)) for the reaction , H_(2)(g) + O_(2)(g) rarrH_(2)O_(2)(g), given that bond enthalpy of H-H,O = O, O-H and O-O ( in kJ mol^(-1))are respectively 438, 498,464 and 138

Calculate the standard enthalpy change ( in kJ mol^(-1)) for the react

1.	Calculate the standard enthalpy change ( in kJ mol^(-1)) for the reaction , H_(2)(g) + O_(2)(g) rarrH_(2)O_(2)(g), given that bond enthalpy of H-H,O = O, O-H and O-O ( in kJ mol^(-1))are respectively 438, 498,464 and 138
Answer» `-1 30` `065` `+130` `- 334` SOLUTION :`H -H(g)+O=O(g) rarr H-O-O-H(g)` `Delta_(R)H= BE(H-H) + BE(O=O)-[2BE(O-H) +BE(O-H)]` `=438 +498 - [2 xx 464 +138 ]KJ mol^(-1)` `= 936- ( 928+ 138 )= - 130 kJ mol^(-1)`