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Calculate the standard enthalpy of formation of CH_(3)OH(l) from the following data: (i) CH_(3)OH(l) + (3)/(2) O_(2)(g)rarr CO_(2)(g) + 2H_(2)O(l),Delta_(r)H^(@)= - 726 kJ mol^(-1) (ii) C(s) + O_(2)(g) rarrCO_(2)(g), Delta_(c) H^(@) = -393kJ mol^(-1) (iii) H_(2)(g)+ (1)/(2)O_(2)(g) rarr H_(2)O(l) , Delta_(f)H^(@) = - 286kJmol^(-1) |
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Answer» Solution :Aim`: C(s) + 2H_(2)(g)+(1)/(2)O_(2)(g) RARR CH_(3)OH(l) , Delta_(r)H^(@) = ?` Eqn.(II) `+2 xx` Eqn. (iii) -Eqn. (i)gives the required eqn. with `DeltaH = -393+2(-286)- ( -726 ) kJmol^(-1)= - 239 KJ mol^(-1)` |
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