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Calculate the standard enthalpy of formation of CH3OH (l) from the following data :(i) CH3OH (l) + 3/2 O2 (g) → CO2 (g) + 2H2O(l) ΔrH° = -726 KJ mol-1(ii) C(s) +O2 (g)→CO2 (g); ΔrH° = – 393 kJ mol–l(iii) H2(g) +1/2 O2(g) →H2O(l) ΔrH° – 286 kJ mol–1 . |
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Answer» Aim : C (s) + 2H2 (g) + 1/2 O2 (g)→ CH3 OH,Δ fH°(l) Eqn. (ii) + 2 × Eqn. (iii) – Eqn. (i) gives the required eqn. with ΔH= – 393 + 2 (–286) – (– 726) kJ mol–1 = |
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