Calculate the standard free energy change Delta G^(@) for the reaction, 2HgO(s) rarr 2Hg(l) + O_(2)(g) Delta H^(@) = 91 kJ mol^(-1) at 298 K, S_((HgO))^(@) = 72.0 JK^(-1) mol^(-1).

Calculate the standard free energy change Delta G^(@) for the reaction

1.	Calculate the standard free energy change Delta G^(@) for the reaction, 2HgO(s) rarr 2Hg(l) + O_(2)(g) Delta H^(@) = 91 kJ mol^(-1) at 298 K, S_((HgO))^(@) = 72.0 JK^(-1) mol^(-1).
Answer» Solution :`Delta S = 2S_(HG)^(@) + S_((O_(2)))^(@) - 25_(HgO)^(@)` `= (2 xx 77.4 + 205 - 2 xx 72.0) JK^(-1) MOL^(-1) = 215.8 JK^(-1) mol^(-1)` `Delta G^(@) = Delta_(r )H^(@) - T Delta_(r )S^(@)` `= 91 kJ mol^(-1) - (298 xx 21538)/(1000) xx kJ mol^(-1)` `= (91 - 64.3) kJ mol^(-1) = 26.69 kJ mol^(-1)`