1.

Calculate the standard free energy change for the reaction, 4NH_(3)(g) + 5O_(2)(g) rarr 2NO(g) + 6H_(2)O(l) Given that the standard free energies of formation (Delta_(r)G^(@)) for NH_(3)(g), NO(g) andH_(2)O(l)are -16.8 , + 86.7 and -237.2 kJ mol^(-1) respectively. Predict the feasibility of the above reaction at the standard state.

Answer»

Solution :Here, we are given
`Delta_(r) G^(@) (NH_(3))= - 16.8 KJ MOL^(-1)`
`Delta_(f)G^(@) (NO) = + 86.7 kJ mol^(-1)`
`Delta_(f) G^(@) (H_(2)O) = -237.2 kJ mol^(-1)`
`:. Delta_(r) G^(@) = SIGMA Delta_(f) G^(@) ` ( Products) `- Sigma Delta_(f) G^(@) `( Reactants ) `= [ 4 xx Delta_(f) G^(@)(NO) + 6xx Delta_(f) G^(@)(H_(2)O) ]-[4 xx Delta _(f) G^(@) ( NH_(3))+ 5 xx Delta G^(@) (O_(2))]`
`= [ 4 xx (86.7) + 6 xx ( -237.2) ]- [ 4 xx ( -16.8) + 5 xx0]= -1009.2 kJ `
Since` Delta_(r) G^(@)` is negative, the process is feasible.


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