Saved Bookmarks
| 1. |
Calculate the standard free energy change for the reaction, 4NH_(3)(g) + 5O_(2)(g) rarr 2NO(g) + 6H_(2)O(l) Given that the standard free energies of formation (Delta_(r)G^(@)) for NH_(3)(g), NO(g) andH_(2)O(l)are -16.8 , + 86.7 and -237.2 kJ mol^(-1) respectively. Predict the feasibility of the above reaction at the standard state. |
|
Answer» Solution :Here, we are given `Delta_(r) G^(@) (NH_(3))= - 16.8 KJ MOL^(-1)` `Delta_(f)G^(@) (NO) = + 86.7 kJ mol^(-1)` `Delta_(f) G^(@) (H_(2)O) = -237.2 kJ mol^(-1)` `:. Delta_(r) G^(@) = SIGMA Delta_(f) G^(@) ` ( Products) `- Sigma Delta_(f) G^(@) `( Reactants ) `= [ 4 xx Delta_(f) G^(@)(NO) + 6xx Delta_(f) G^(@)(H_(2)O) ]-[4 xx Delta _(f) G^(@) ( NH_(3))+ 5 xx Delta G^(@) (O_(2))]` `= [ 4 xx (86.7) + 6 xx ( -237.2) ]- [ 4 xx ( -16.8) + 5 xx0]= -1009.2 kJ ` Since` Delta_(r) G^(@)` is negative, the process is feasible. |
|