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Calculate the standard free energy for a reaction X hArr Y, if the value of equilibrium constant is 1.8 xx 10^(-7) at 298 K. |
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Answer» Solution :We know that `Delta G^(@) = -2.303 RT LOG K` `= 2.303 XX 8.314 JK^(-1) mol^(-1) xx 298 K xx log.18 xx 10^(-7)` `Delta G^(@) = 38.484 KJ mol^(-1)` |
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