Calculate the temperature at which 28 g of N_2 will occupy a volume of 10.0 litres at 2.46 atmospheres.

Calculate the temperature at which 28 g of N_2 will occupy a volume of

1.	Calculate the temperature at which 28 g of N_2 will occupy a volume of 10.0 litres at 2.46 atmospheres.
Answer» Solution :At S.T.P. (1 atm and 273 K), 28 G of `N_2` (one mole) occupy 22.4 L.According to the gas equation, `(P_1 V_1)/T_1 =(P_2 V_2)/T_2` In the PRESENT case, `P_1 = 1" atm,""" V_1 = 22.4L, ""T_1 = 273 K " and "P_2 = 2.46 " atm, "V_2 = 10.0 L, "" T_2`= ? On SU(bstituting the VALUES, we have `(1xx 22.4)/273 = (2.46xx10.0)/(T_2)` `T_2 = 299.8 = 300 K` Hence, the required temperature is 300 K or `27^@C` .