1.

Calculate the temperature at which the average speed of oxygen equals that of hydrogen at 20 K.

Answer»


Solution :`BAR c_(CO_(2))=sqrt((8RT)/(pixx32)),barc_(H_(2))=sqrt((8Rxx20)/(pixx2))," As "bar c_(CO_(2))=bar c_(H_(2)),(8RT)/(pixx32)=(8Rxx20)/(pixx2)"or"T=320 K`


Discussion

No Comment Found