1.

Calculate the temperature at which the oxygen molecules will have the same rms velocity as the hydrogen molecules at 150^@C. Molecular weight of oxygen is 32 and that of hydrogen is 2.

Answer»

SOLUTION :`v_(rms)=SQRT((3RT)/(M))" As "v_(1 rms)=v_(2 rms)`, therefore `T ALPHA M`
`T_(1)/T_2=(M_(1))/M_2, T_(2)=T_(1) (M_2/M_1), T_2=423 [(32)/2]`
`T_2=6768k, t_2=6768-273=6495^@C`


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