1.

Calculate the temperature at which28 g of N_(2) will occupy a volume of 10.0 litres 2.46 atmosphere.

Answer»

Solution :28 g `N_(2)`=1 MOLE of `N_(2)`.
ApplyingPV=nRT,`2.46xx10=1xx0.0821xxT`. This gives T=299.6 K


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