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Calculate the temperature of 14 mol of a gas occupying 10 dn^(3) at 3.32 bar pressure (R=0*083 bar dm^(3)"mol"^(-1)K^(-1)) |
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Answer» Solution :Here `n=14= "mol" v= dm ^(3), p=3*32 ` bar `pv= nRT or T=(PV)/(nR)` `t=(3*32 "bar"xx 10 dm^(3))/(14 "mol" xx 0*083dm^(3))"bar" K^(-1)"mol"^(-1) =28*57K or -244*57^(@)C` `:. T-244*27^(@)C` |
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