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Calculate the temperature of 4.0 mol of a gas occupying 5 dm^3 at 3.32 bar (R = 0.083 " bar " dm^3 K^(-1)mol^(-1)). |
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Answer» SOLUTION :ACCORDING to the gas EQUATION, `PV = nRT` or `T= (PV)/(nR)= (3.32 xx 5)/(4.0xx0.083)=50 K` |
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