Calculate the temperature of 4.0 mol of a gas occupying 5 dm^(3) at 3.32 bar. (R = 0.083 bar dm^(3)K^(-1)mol^(-1)).

Calculate the temperature of 4.0 mol of a gas occupying 5 dm^(3) at 3.

1.	Calculate the temperature of 4.0 mol of a gas occupying 5 dm^(3) at 3.32 bar. (R = 0.083 bar dm^(3)K^(-1)mol^(-1)).
Answer» Solution :ACCORDING to combined gas equation, pV = nRT `therefore T=(pV)/(nR)` Where Pressure of gas (p) = 3.32 BAR Volume of gas `(V) = 5 dm^(3)` Moles of gas (N) = 4.0 mol gas constant (R ) = 0.083 bar `dm^(3)K^(-1)mol^(-1)` `therefore T=(("3.32 bar")(5 dm^(3)))/((4.0 mol)(0.083" bar dm"^(3)K^(-1)mol^(-1)))` `= 50 K = (50-273)=-223^(@)C`.