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| 1. |
Calculate the temperature of 4.0 moles of a gas occupying 5 dm^(3) at 3.32 bar (R=0.083 bar dm^(3)K^(-1)mol^(-1)) |
| Answer» Solution :PV=nRTor`T=(PV)/(NR)=(3.32" ABR"xx5dm^(3))/(4.0 molxx0.083" BAR" dm^(3)K^(-1)mol^(-1))=50 K` | |