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Calculate the temperature which has same numeral value on celsius and Fahrenheit scale. |
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Answer» Solution :`(""^(@)F-32)/(180)=(""^(@)C)/(100)` SUPPOSE, `F=C=Q` `:.(Q-32)/(180)=Q/100` `:.Q-32=(180)/(100)Q` `:.Q-9/5Q=32` `:.-(4Q)/(4)=32` `:.Q=-(32xx5)/(4)` `:.Q=-40` `:.Q=-40" "^(@)F` or `Q=-40" "^(@)C` |
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