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Calculate the tempurature when 54 gm of glucose present in 250 gm of waterfreeze. Kf 1.86 kg Mat-1 |
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Answer» Molality of the glucose =no of mole of glucose in 1 kg of waterNo of mole of glucose =weight of the glucse/molecular weight of the glucose =54/180 =.3we have ,delta Tf=Kfmdelta Tf= (1.86*.3)/.250=2.232temperature at which it will freeze=273 -2.232 K =270.768 K |
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