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Calculate the terminal velocity with which an air bubble of diameter 0.8 mm rises in a liquid of viscosity 0.250 Ns//m^(2) and density 0.95 x 10^(3)kg//m^(3). Density of air is 1.3 kg//m^(3) |
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Answer» SOLUTION :` ""a= 0.4 xx 10 ^(-3)m, sigma = 0.95 xx 10 ^(3) = 950 kg//m^(3),rho =1.3 kg//m^(3)` `"" eta = 0.250 Ns//m^(2), "" v= ? ` ` "" v= (2(rho -sigma) a^(2)g)/( 9 eta)= ( 2xx (1.3 - 950 )xx(0.4 xx 10 ^(-3))^(2))/( 9xx 0.250 ) ` ` "" = - 0. 135 xx 10^(-3) m//s` |
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