Calculate the time to deposit 1.5 g of silver at cathode when a current of 1.5 A is passed through the solution of `AgNO_(3)`.

Calculate the time to deposit 1.5 g of silver at cathode when a curren

1.	Calculate the time to deposit 1.5 g of silver at cathode when a current of 1.5 A is passed through the solution of `AgNO_(3)`.
Answer» The reaction at the cathode is : `{:(Ag^(+)(aq)+e^(-)rarr Ag(s)),(108 g " "96500 C):}` 108 g of silver is deposited by passing charge =96500 C 1.5 g of silver is deposited by passing charge `=((96500 C)xx(1.5 g))/((108 g))=1340.27 C =1340.27 `As Time to deposited 1.5 g of silver `=("charge"(Q))/("current"(I))=((1340.27 As))/((1.5 A))` =893.51 s or 14.85 min

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Calculate the time to deposit 1.5 g of silver at cathode when a current of 1.5 A is passed through the solution of `AgNO_(3)`.

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