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Calculate the torque on a `200` turns rectangular coil of length `20cm` and breadth `10cm` carrying a current of `10A`, when placed in a magnetic field. The plane of the coil is making an angle of `60^@` with a magnetic field of `4T`. |
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Answer» Correct Answer - `80N-m` Here, `n=200`, `l=20cm=0*20m`, `b=10cm=0*10m` `B=4T`, `A=lxxb=0*20xx0*10=0*02m^2`, `I=10A`. Angle between `vecB` and normal on the plane of the coil `theta=90^@-60^@=30^@` Torque, `tau=nIBA sin theta` `=200xx10xx4xx0*02xxsin30^@=80N-m` |
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