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| 1. |
Calculate the total no of bicarbonate ions present in fused or molten Mg(HCo3)2 having mass 146grams |
| Answer» Moles of Mg(HCO3)2 =GIVEN MASS/MOLAR MASS=146/146===1 MOLEsince, 1 mole=6.022 *10²³ particles /ions of Mg(HCO3)2so, (HCO3)2 IONS present in given compound will be===2*6.022*10²³=12.044 * 10²³ ions... Because 2 moles of bicarbonate ion is present in 1 mole of magnesium hydrogen carbonate... | |