Calculate the total no. of degrees of freedom possessed by the molecul

1.	Calculate the total no. of degrees of freedom possessed by the molecules in 1cm3 of H2 gas at NTP.
Answer» No. of H₂ Molecules in 22.4 liters or 22400 cm³at NTP = 6.02 x 10²³. ∴ No. of H₂Molecules in 1 cm³ at NTP = (6.02 x 10²³)/22400 = 2.6875 x10¹⁹. No. of degrees of freedom associated with each H₂(a diatomic) molecule = 5 ∴ Total no. of degree of freedom associated with 1cm³ gas = 2.6875 x 10¹⁹ x 5 = 1.3475 x 10²⁰.

Calculate the total no. of degrees of freedom possessed by the molecules in 1cm3 of H2 gas at NTP.

Answer»

No. of H₂ Molecules in 22.4 liters or 22400 cm³at NTP = 6.02 x 10²³.

∴ No. of H₂Molecules in 1 cm³ at NTP = (6.02 x 10²³)/22400 = 2.6875 x10¹⁹.

No. of degrees of freedom associated with each H₂(a diatomic) molecule = 5

∴ Total no. of degree of freedom associated with 1cm³ gas

= 2.6875 x 10¹⁹ x 5 = 1.3475 x 10²⁰.