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Calculate the total number of electrons present 1.4 g of dinitrogen gas. |
Answer» Correct Answer - `4.2154xx10^(23)` electrons Molar mass of dinirogen `(N_(2))=28g mol^(-1)` Thus, 1.4 g of `N_(2)=(1.4)/(28)=0.05 mol` `=0.05xx6.02xx10^(23)` number of molecules `=3.01xx10^(23)` number of molecules Now, 1 molecule of `N_(2)` contains 14 electrons. Therefore, `3.01xx10^(23)` molecules of `N_(2)` contains `=14xx3.01xx1023=4.214xx10^(23)` electrons |
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