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Calculate the total number of electrons present in 1.4 dinitrogen gas. (N of Z = 7). |
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Answer» Solution :Moleculasr formula of DINITROGEN gas `= N_(2)` Molecular mass is 28 g `mol^(-1)` Moles of `N_(2)=("Weight")/("Molecular mass of "N_(2))` `= (1.4 g)/(28 g mol^(-1))=0.05` mole `N_(2)` gas ATOMIC NUMBER of Nitrogen (Z) = 7 1 mole of Dinitrogen `7xx2=14` electron `THEREFORE` 1 mole `= 6.023xx10^(23)` molecules of `N_(2)` Number of ELECTRONS in 1 mole Dinitrogen `= 14xx6.022xx10^(23)` But number of electrons present in 0.05 moles Dinitrogen `bar(e )=14xx("0.05 mole")xx(6.022xx10^(23)bar(e )mol^(-1))` `= 14xx0.3011xx10^(23)` electrons `=4.2154xx10^(23)` electrons. |
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