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Calculate the total number of electrons present in 17g of ammonia. |
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Answer» Solution :No. of ELECTRONS present in one AMMONIA `(NH_(3))` molecule (7+3)=10 No. of moles of `NH_(3)=` `(Mass )/("Molar mass")=(17g)/(17gmol^(-1))=1mol` No .of molecules present in 1 mol of `NH_(3)=6.023xx10^(23)` No. of electrons present in 1 mol of `NH_(3) ` `""=10xx6.023xx10^(23)` `""=6.023xx10^(24)` |
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