1.

Calculate the total number of electrons present in 17g of ammonia.

Answer»

Solution :No. of ELECTRONS present in one AMMONIA `(NH_(3))` molecule (7+3)=10
No. of moles of `NH_(3)=`
`(Mass )/("Molar mass")=(17g)/(17gmol^(-1))=1mol`
No .of molecules present in 1 mol of `NH_(3)=6.023xx10^(23)`
No. of electrons present in 1 mol of `NH_(3) `
`""=10xx6.023xx10^(23)`
`""=6.023xx10^(24)`


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