1.

Calculate the total number of electrons present in `3.2 g` of oxygen gas.

Answer» (Atomic numbe of `O = 8`, number of electrons in `O_(2) = 16`)
`3.2 g of O_(2) = (3.2)/(932) = 0.1 mol`
`0.1 xx 6.022 xx 10^(23)` molecules
`= 6.002 xx 10^(22)` molecules
`= 6.022 xx 10^(22) xx 16` electrons
`= 9.635 xx 10^(23)` electrons


Discussion

No Comment Found

Related InterviewSolutions