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Calculate the total number of electrons present in `3.2 g` of oxygen gas. |
Answer» (Atomic numbe of `O = 8`, number of electrons in `O_(2) = 16`) `3.2 g of O_(2) = (3.2)/(932) = 0.1 mol` `0.1 xx 6.022 xx 10^(23)` molecules `= 6.002 xx 10^(22)` molecules `= 6.022 xx 10^(22) xx 16` electrons `= 9.635 xx 10^(23)` electrons |
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