InterviewSolution
Saved Bookmarks
InterviewSolution
| 1. |
Calculate the total percentage of oxygen in FeSO4.7H2O. ( Fe=56, S=32, O=16, H=1 ) |
|
Answer» mula mass of FERROUS sulphateAt.massofFe+At.,massofS+At.massofoxygen+7×Mol.massofH 2 O56.0+32.0+4×16.0+7×18.0=278.0So % of water of CRYSTALLISATION = 278126 ×100=45.32 % of IRON = 27856 ×100=20.14% of sulphur = 27832 ×100=11.51% of oxygen = 27864 ×100=23.02(Oxygen present in water molecules is not taken into account.) please mark me to brainlist |
|