Calculate the total pressure in a mixture of 8 g os dioxygen and 4 g of dihydrogen confined in a vessel of 1 dm^(3) at 27^(@)C.(R = 0.083 bar dm^(3)K^(-1)mol^(-1))

Calculate the total pressure in a mixture of 8 g os dioxygen and 4 g o

1.	Calculate the total pressure in a mixture of 8 g os dioxygen and 4 g of dihydrogen confined in a vessel of 1 dm^(3) at 27^(@)C.(R = 0.083 bar dm^(3)K^(-1)mol^(-1))
Answer» Solution :Calculation of dioxygen mole `(n_(1))` :Molecular mass of dioxygen `= 2(16)=32 g mol^(-1)` Weight of mass = 8 g `therefore` Mole of dioxygen `= ("Mass")/("Molecular mass")` `=(8g)/(32 g mol^(-1))=0.25 mol = n_(1)` Calculation of dihydrogen mole `(n_(2))` :Molecular mass of dihydrogen `= 2.0 g mol^(-1)` Weight of mass = 4.0 g `therefore` Mole of dihydrogen `=("Mass")/("Molecular mass")` `= (4.0 g)/(2.0 g mol^(-1))=2.0 mol = n_(2)` Total mole `(n)=(n_(1)+n_(2))` `= 0.25 mol O_(2)+2.0 mol H_(2)` = 2.25 mol where, Volume of vessel `(V) = 1dm^(3)` Temperature `(T)=(27+273)K = 300K` R = 0.083 bar `dm^(3)K^(-1)mol^(-1)` pV = NRT and `p=(nRT)/(V)` `therefore p =((2.25 mol)(0.083" bar dm"^(3)K^(-1)mol^(-1))(300 K))/(1 dm^(3))` = 56.025 bar pressure.