Calculate the uncertaimty in position of an electron,if /_\v=0.1% and

1.	Calculate the uncertaimty in position of an electron,if /_\v=0.1% and v=2.2 xx 10^(6) ms^(-1)
Answer» Solution :MASS of an electron`=m=9.1xx10^(-31)KG`. `/_\V`=UNCERTAINTY in velocity `=(0)/(100)xx2.2xx10^(6)ms-1` `/_\x./_\v.m=h/(4pi)` `/_\x=h/(/_\v.mxx4pi)` `=(6.626xx10^(-34))/(2.2xx10^(3)xx9.1xx10^(-31)xx4xx3.14)` `=(6.626xx10^(-6))/(251.45)` `=0.02635xx10^(-6)` `/_\x=2.65xx10^(-6)` Uncertainty in position`=2.635xx10^(-10)m`.

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