Calculate the uncertainty in position of an electron, if Deltav = 0.1%

1.	Calculate the uncertainty in position of an electron, if Deltav = 0.1% and v = 2.2 xx 10^(6) ms^(-1)
Answer» Solution :MASS of an electron = `m= 9.1xx10^(-31) kg` ` Deltav = "Uncertainty in velocity" = (0.1)/(100)xx2.2xx10^(6) ms^(-1)` `Deltav = 0.22x10^(4) = 2.2 x 10^(3) ms^(-1)` `DeltaX.DeltaV.m=(H)/(4pi)` `DeltaX=(h)/(Deltav.mxx4pi)=(6.626xx10^(-34))/(2.2xx10^(3)xx9.1xx106(-31)xx4xx3.14)``Deltax=2.635xx10^(-8)` `"Uncertainty in position" = 2.635xx10^(-8)m`

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