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Calculate the uncertainty in the velocity of an electron, if the uncertainity in position is 100 pm. |
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Answer» Solution :Given `Deltaxx="100 PM "=100xx10^(-12)m=10^(-10)m` `"mass of electron, m"=9.1xx10^(-31)kg` `Deltav=?""pi=3.1416` `Deltax xx Deltav=(h)/(4pim)` `Deltav=(h)/(4pim. Deltax)=(6.625xx10^(-34)"kgm"^(2)s^(-1))/(4xx3.1416xx9.1xx10^(-31)kgxx10^(-10))` `=5.8xx10^(5)MS^(-1)` `"The uncertainty in VELOCITY"=5.8xx10^(5)ms^(-1)` |
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