1.

Calculate the value of Avogadro's number from the following data: Density of NaCl=2.165 g cm^(-3). Distance between Na^+ and Cl^- in NaCl=281 pm

Answer»

Solution :A unit cell of NaCl CONTAINS 4 NaCl units, THEREFORE , Z=4 , M=23+35.5=`58.5 g MOL^(-1), RHO =2.165 g cm^(-3)`
As distance between `Na^+` and `Cl^-` =281 pm `therefore` Edge of the unit cell =`2xx281`=562 pm
(Edge is the distance from `Na^+` to `Na^+` ion or `Cl^-` to `Cl^-` ion.
Substituting these values in the expression , `rho=(ZxxM)/(a^3xxN_0)`
`2.165 g cm^(-3)=(4xx58.5 g mol^(-1))/((562xx10^(-10) cm)^3 xxN_0)` or `N_0=6.09xx10^23 mol^(-1)`


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