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Calculate the value of (DeltaH - DeltaE)in calories for the combustion of CH_4 at 27^@C. |
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Answer» Solution :`CH _(4 (g)) + 2O _(2 (g)) to CO _(2 (g)) + 2H _(2) O _((L))` CHANGE in the number of moles, `DELTAN n = n _(P) - n _(R) =1 -3 =-2, Delta H = Delta E + Delta n RT` `Delta H - Delta E =- 2 XX 2 xx 300 =-1200 ` calories. |
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