Calculate the value of DeltaU and DeltaH on heating 128.0 g of oxygen from 0^@C to 100^@C. CV and C_p on an average are 21 and 29 J "mol"^(-1) K^(-1)(The difference is 8J "mol"^(-1) K^(-1)which is approximately equal to R )

Calculate the value of DeltaU and DeltaH on heating 128.0 g of oxygen

1.	Calculate the value of DeltaU and DeltaH on heating 128.0 g of oxygen from 0^@C to 100^@C. CV and C_p on an average are 21 and 29 J "mol"^(-1) K^(-1)(The difference is 8J "mol"^(-1) K^(-1)which is approximately equal to R )
Answer» Solution :We KNOW `DeltaU=n C_V(T_2-T_1)` `DELTAH=n C_P (T_2-T_1)` Here `n=128/32` 4 moles , `T_2=100^@C`=373 K , `T_1=0^@`C =273 K `DeltaU=nC_V(T_2-T_1)` `DeltaU` = 4 x 21 x (373-273 ) `DeltaU` =8400 J `DeltaU` =8.4 kJ `DeltaH= nC_P (T_2-T_1)` `DeltaH`=4 x 29 x (373-273) `DeltaH` =11600 J `DeltaH`=11.6 kJ