1.

Calculate the value of ΔrG0 at 298 K for the cell reaction. 3Mg(s) + 2Al3+aq → 3Mg2+aq + 2Al(s) [Given; EoMg = -2.36 V, EEoAl = -1.66 V and F = 96487 C]

Answer»

E0cell = E0Al – E0Mg 

= -1.66 – (-2.36) = 0.7v 

ΔG0 = -nE0

= -6 × 0.7 × 96487 

= 405.24KJ



Discussion

No Comment Found

Related InterviewSolutions