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Calculate the value of ΔrG0 at 298 K for the cell reaction. 3Mg(s) + 2Al3+aq → 3Mg2+aq + 2Al(s) [Given; EoMg = -2.36 V, EEoAl = -1.66 V and F = 96487 C] |
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Answer» E0cell = E0Al – E0Mg = -1.66 – (-2.36) = 0.7v ΔG0 = -nE0F = -6 × 0.7 × 96487 = 405.24KJ |
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