Calculate the value of log K_(p) for the reaction N_(2)(g)+3H_(2)(g) hArr 2NH_(3)(g) at 25^(@)C. The standardenthalpy of formation of NH_(3)(g)is-46kJ and standard entropiesof N_(2)(g), H_(2)(g) andNH_(3)(g) areare 191,130,193JK^(-1) mol^(-1) respectively . ( R = 8.3 JK^(-1) mol^(-1))

Calculate the value of log K_(p) for the reaction N_(2)(g)+3H_(2)(g) h

1.	Calculate the value of log K_(p) for the reaction N_(2)(g)+3H_(2)(g) hArr 2NH_(3)(g) at 25^(@)C. The standardenthalpy of formation of NH_(3)(g)is-46kJ and standard entropiesof N_(2)(g), H_(2)(g) andNH_(3)(g) areare 191,130,193JK^(-1) mol^(-1) respectively . ( R = 8.3 JK^(-1) mol^(-1))
Answer» SOLUTION :`Delta_(f)G^(@)(NH_(3)) = DeltaH^(@) - TDeltaS^(@) = -46000- ( 298 xx192) J MOL^(-1) = - 103.2 KJ mol^(-1)` `Delta_(f)G^(@)(N_(2))= DeltaH^(@) - T DeltaS^(@) = 0 -298 xx191 J mol^(-1) = -56.9 kJ mol^(-1)` `Delta_(f)G^(@)( H_(2)) = DeltaH^(@) - T DeltaS^(@) =0 - 298 xx 130 J mol^(-1) = - 38.74kJ mol^(-1)` `DeltaG^(@)` for reaction `Delta _(r)G^(@) = 2 xx Delta_(f)G^(@) ( NH_(3))- Delta_(f)G^(@) ( N_(2))-3Delta_(f)(H_(2)) =- 206.4 +56.9 +116.2 = - 33.28 kJ mol^(-1)- DeltaG^(@) =2.303 RT log K` `33.28 = 2.303 xx (8.314 xx 10^(-3)) log K`or `log K =1.738 xx 10^(3)`