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Calculate the values of DeltaU and DeltaH for an ideal gas in terms of C_P and C_V. |
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Answer» SOLUTION :Calculation of `DELTAU` and `DeltaH`: For one mole of an IDEAL gas , we have `C_V=(dU)/(dT)` `dU=C_V. dT` For a finite change , we have `DeltaU=(U_2-U_1)=C_V(T_2-T_1)` and for n moles of an ideal gas we get `DeltaU=n C_V (T_2-T_1)`...(1) We KNOW, `DeltaH=Delta(U+PV)` `DeltaH=DeltaU+Delta(PV)` `DeltaH=DeltaU+DeltaRT`[`because` PV=RT] `DeltaH=DeltaU+RDeltaT` `DeltaH=C_V(T_2-T_1)+R(T_2-T_1)` `DeltaH=(C_V+R)(T_2-T_1)` `DeltaH=C_P(T_2-T_1) "" [because C_P -C_V=R]` For n moles of an ideal gas we get `DeltaH=n C_P(T_2-T_1)`....(2) |
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