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Calculate the velocity of an electron in the first Bohr orbit of a hydrogen atom |
Answer» Assume `n = 1`, take `Z = 1`, and insert the values of the constants to obtain `V_(1) = ((2)(3.14)(1)(4.8xx10^(-10)esu)^(2))/((1)(6.63xx10^(-27)erg s))` `= 2.18 xx 10^(8)cm s^(-1)` `= 2.18 xx 10^(6) m s^(-1)` |
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