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Calculate the velocity of an electron in the second Bohr orbit of `Be^(3+)`. Strategy: Use Eq. with proper values of `n` and `Z`. Atomic number of the `Be` atom is `4`. |
Answer» `V_(2) = (ZV_(1))/(n) = ((4)(2.18xx10^(6)ms^(-1)))/(2)` `4.36xx10^(6)ms^(-1)` |
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