Calculate the velocity of the centre of mss of the system of particles

1.	Calculate the velocity of the centre of mss of the system of particles shown in figure.
Answer» `m_1=1.0kg` `V_1=(-15 cos 37^0veci-1.5sin37^0vecj)` `m_2=1.2kg` `V_2=0.4vecj` `m_3=1.5kg` `V_3=-1.0cos37^0veci+1.0sin37^0vecj`)` `m_4=0.50kg` `V_4=3.0veci` `m_5=1.0kg` `V_5=2.0cos37^0veci-2.0sin37^0vecj` `V_(cm)=(m_1 v_1+m_2v_2+m_2v_3+m_4v_4+m_5v_5)/(m_1+m_2+m_3+mK_4+m_5)` `1/(1.0+1.2+1.5+1.0+0.50)^([1.0(-1.5xx4/5veci-1.5xx3/5vecj)+...-2.0xx3/5vecj])` `=0.20m/s at 45^0` below the direction towards right,

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Calculate the velocity of the centre of mss of the system of particles shown in figure.

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