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Calculate the velocity with which the liquid gushes out of the `4cm^(2)` outlet, if the liquid flowing in the tube is water and liquid in `U` tube has a specific gravity `12`. Velocity of liquid at point `A` is `sqrt(20.2)m//s` A. `2.5 m//s`B. `5.5 m//s`C. `8 m//s`D. `10 m//s` |
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Answer» `P_(A)+(1)/(2)rhov_(A)^(2)=P_(B)+(1)/(2)rhov_(B)^(2)` `P_(A)-P_(B)=(1)/(2)rho(v_(B)^(2)-v_(A)^(2))` `0.02xx12000xx10=(1)/(2)xx1000(v_(B)^(2)-20.2)` `4.8=v_(B)^(2)-20.2rArrv_(B)=5m//s` `rArr A_(3).v_(B)=A_(1)v_(1)+A_(2)v_(2)` `rArr 30=4v_(1)+8` `rArr 4v_(1)=22rArrv_(1)=(22)/(4)=5.5m//s` |
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