Calculate the voltage `E` of the cell at `25^(@)C` `Mn(s) |Mn(OH_(2))(s)|Mn^(2+)(x,M)OH^(-) (1.00 xx 10^(-4)M)||Cu^(2+) (0.675M)|Cu(s)` given that `K_(sp) = 1.9 xx 1-^(-13)` for `Mn(OH)_(2)(s) E^(@) (Mn^(2+)//Mn) =- 1.18 V, E^(@) (Cu^(+2)//C) = +0.34V`

Calculate the voltage `E` of the cell at `25^(@)C` `Mn(s) |Mn(OH_(2))(

1.	Calculate the voltage `E` of the cell at `25^(@)C` `Mn(s) \|Mn(OH_(2))(s)\|Mn^(2+)(x,M)OH^(-) (1.00 xx 10^(-4)M)\|\|Cu^(2+) (0.675M)\|Cu(s)` given that `K_(sp) = 1.9 xx 1-^(-13)` for `Mn(OH)_(2)(s) E^(@) (Mn^(2+)//Mn) =- 1.18 V, E^(@) (Cu^(+2)//C) = +0.34V`
Answer» Correct Answer - `1.66V` `Mn rarr Mn^(2+) +2e^(-)` `Cu^(2+) +2e^(-) rarr Cu K_(sp) = [Mn^(2+)] [OH^(-)]^(2)` `E = (1.18 +0.34) - (0.0591)/(2) log. ([Mn^(2+)])/([Cu^(2+)])` `E_(cell) = 1.66V`

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Calculate the voltage `E` of the cell at `25^(@)C` `Mn(s) |Mn(OH_(2))(s)|Mn^(2+)(x,M)OH^(-) (1.00 xx 10^(-4)M)||Cu^(2+) (0.675M)|Cu(s)` given that `K_(sp) = 1.9 xx 1-^(-13)` for `Mn(OH)_(2)(s) E^(@) (Mn^(2+)//Mn) =- 1.18 V, E^(@) (Cu^(+2)//C) = +0.34V`

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