Calculate the volume at N.T.P occupied by (i) 14 g of nitrogen (ii) 1.5 gram moles of carbon dioxide (iii) 10^(21) molecules of oxygen.

Calculate the volume at N.T.P occupied by (i) 14 g of nitrogen (ii)

1.	Calculate the volume at N.T.P occupied by (i) 14 g of nitrogen (ii) 1.5 gram moles of carbon dioxide (iii) 10^(21) molecules of oxygen.
Answer» Solution :(i) 28.0 g of NITROGEN at N.T.P occupy = 22.4 L 14.0 g of nitrogen at N.T.P occupy `= (14.0)/(28.0)xx22.4 = 11.2 L` (ii) 1.0 mole of `CO_(2)` at N.T.P occupy = 22.4 L 1.5 moles of `CO_(2)` at N.T.P occupy at N.T.P `= 22.4 xx 1.5 = 33.6 L` (III) `6.022 xx 10^(23)` molecules of oxygen at oxygen at N.T.P occupy `= 22400 CM^(3)` `10^(21)` molecules of oxygen at N.T.P occupy `= (10^(21))/(6.022xx10^(23))xx22400=37.2 cm^(3)`.