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Calculate the volume occupied by 16 grm O_(2)at 300 K and 8.31 MPa if (P_(c)V_( c))/(RT_( c))= 3/8 and (P_(t)V_(t))/T_(t)=2.21(Given : R = 8.314 Mpa/K-mol) |
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Answer» 125.31 ML `V_m o= 3/8 xx 2.21 xx (RT)/P = 248.625 ml`. `V_L = 16/32 xx 248.625 = 124.31 ml`. |
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