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Calculate the volume occupied by 8.8 g of CO_(2) at 31.1^(@)C and 1 bar pressure. R = 0.083 bar L K^(-1)mol^(-1). |
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Answer» SOLUTION :ACCORDING to ideal gas equations, PV = nRT `therefore V=(nRT)/(p)` but mole `= n=("Weight"_((g)))/("Molar mass (M)")` `therefore V=(gRT)/(Mp)` where, g = 8.8 gram R = 0.083 bar L `K^(-1)mol^(-1)` `T=31.1^(@)C=(31.1+273)K=304.1K` M = molar mass of `CO_(2)=(12+32)=44g mol^(-1)` p = 1 bar `V=((8.8g)(0.083" bar L K"^(-1) mol^(-1))(304.1 K))/((44g mol^(-1))("1 bar"))` `= 5.04806 L ~~ 5.048 L` |
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