1.

Calculate the volume occupied by `8.8 g` of `CO_(2)` at `31.3^(@)C` and `1` bar pressure. `(R = 0.083 "bar" L K^(-1) mol^(-1))`

Answer» `P=1 bar, T=33.1+273=304.1 K`
`W_(CO_(2))=8.8 g, m_(CO_(2))=44`
`PV=(W//m)RT`
`1xxV=8.8/44xx0.083xx304.1`
`V=5.05 L`


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