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Calculate the volume occupied by `8.8 g` of `CO_(2)` at `31.3^(@)C` and `1` bar pressure. `(R = 0.083 "bar" L K^(-1) mol^(-1))` |
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Answer» `P=1 bar, T=33.1+273=304.1 K` `W_(CO_(2))=8.8 g, m_(CO_(2))=44` `PV=(W//m)RT` `1xxV=8.8/44xx0.083xx304.1` `V=5.05 L` |
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