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Calculate the volume occupied by 8.8 g of `CO_(2)` at `31.1^(@)C` and 1 bar pressure. R= 0.083 bar L `K^(-1)mol^(-1).` |
Answer» Correct Answer - 5.05 L It is known that, `pV=m/MRT` `rArr V=(mRT)/(Mp)` Here, m = 8.8 g R= 0.083 bar `LK^(-1)mol^(-1)` T = `31.1^(@)C` = 304.1 K M =44 g p = 1 bar Thus, volume `(V)=(8.8xx0083xx304.1)/(44xx1)` `" "=5.04806 L` `" "5.05L` Hence, the volume occupied is 5.05 L. |
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