Calculate the volume of 0.3 moles of HCl4.4g of CO₂34g of NH₃

1.	Calculate the volume of 0.3 moles of HCl4.4g of CO₂34g of NH₃
Answer» ANSWER: We know that volume of 1 mole = 22.4 litres i)0.3 moles of HCL = 0.3 x 22.4 = 6.72 L ii) 4.4 g of CO₂ = 4.4/44 = 0.1 moles Volume = 0.1 x 22.4 = 2.24 l iii) 34 g of NH₃ = 34/17 = 2 moles Volume = 2 x 22.4 = 44.8 l

Answer»

We know that volume of 1 mole = 22.4 litres

i)0.3 moles of HCL = 0.3 x 22.4 = 6.72 L

ii) 4.4 g of CO₂ = 4.4/44 = 0.1 moles

Volume = 0.1 x 22.4 = 2.24 l

iii) 34 g of NH₃ = 34/17 = 2 moles

Volume = 2 x 22.4 = 44.8 l

Discussion