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Calculate the volume of 10 volume `H_(2)O` solution that will react with 200 mL of 2N `KMnO_(4) ` in acidic medium.

Answer» Normality of 10 volume `H_(2)O_(2)=("Volume strength")/(5.6)=(10)/(5.6) N`
Applying normality equation, `N_(1)V_(1)(H_(2)O_(2))=N_(2)V_(2)(KMnO_(4)`
`(10)/(5.6)xxV_(1)=2xx200` or `V_(1)=(2xx200xx5.6)/(10)=224` mL.


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