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Calculate the volume of 38% solution ofHal to make a L of 0.1 m Ha solution( Density of giver ha = 1.20 g/mol |
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Answer» density of solution = 1.19 GLML MOLARITY = MolarmassofHCl 1.19 ×1000×38% = 36.5 1.19 ×1000× 100 38
12.389m mole of HCl required to make 10 L of all 0.1MHCl=10×0.1=1mole 12.389×v=1 v= 12.389 1 =80.7ml Explanation: |
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