1.

Calculate the volume of CSTR in litre required to achieve 70% conversion. The feed contains 10 molA/litre with feed rate of 3 lit/min and rate constant 0.15 for the reaction -rA = k(CA)^1.5.(a) 3(b) 9(c) 18(d) 27I have been asked this question during an online interview.The doubt is from Design Equations for Flow Reactors in portion Ideal Reactors for a Single Reaction, Conversion and Reactor Sizing of Chemical Reaction Engineering

Answer»

The correct ANSWER is (d) 27

Easiest explanation: \(\frac{τ}{CA0} = \frac{XA}{-rA} = \frac{XA}{k(CA0(1-XA))^{1.5}} \)

τ = \(\frac{0.7*10}{0.15(10(1-0.7))^1.5} \)

τ = \(\frac{V}{V0} \) = 8.981 min

V = 8.98*3 = 26.94 LIT .



Discussion

No Comment Found

Related InterviewSolutions